The sides of a triangle are in the ratio frac | vedclass

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(B) The ratio of the sides is given as $\frac{1}{2}: \frac{1}{3}: \frac{1}{4}$.To simplify this ratio,multiply each term by the least common multiple

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(B) The ratio of the sides is given as $\frac{1}{2}: \frac{1}{3}: \frac{1}{4}$.To simplify this ratio,multiply each term by the least common multiple $(LCM)$ of the denominators $(2, 3, 4)$,which is $12$.Ratio $= (\frac{1}{2} 	imes 12) : (\frac{1}{3} 	imes 12) : (\frac{1}{4} 	imes 12) = 6 : 4 : 3$.Let the sides be $6x, 4x,$ and $3x$.The perimeter of the triangle is the sum of its sides: $6x + 4x + 3x = 13x$.Given that the perimeter is $104 \, cm$,we have $13x = 104$.Solving for $x$: $x = \frac{104}{13} = 8$.The longest side corresponds to the largest ratio value,which is $6x$.Longest side $= 6 	imes 8 = 48 \, cm$.

The sides of a triangle are in the ratio $\frac{1}{2}: \frac{1}{3}: \frac{1}{4}$ and its perimeter is $104 \, cm$. The length of the longest side (in $cm$) is:

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