The sides of a triangle are in the ratio 1/2 | vedclass

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(C) The ratio of the sides is given as $a : b : c = 1/2 : 1/3 : 1/4$.To simplify this ratio,multiply each term by the least common multiple $(LCM)$ of

Vedclass · Accepted Answer

$72$

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(C) The ratio of the sides is given as $a : b : c = 1/2 : 1/3 : 1/4$.To simplify this ratio,multiply each term by the least common multiple $(LCM)$ of the denominators $(2, 3, 4)$,which is $12$.$a : b : c = (1/2 	imes 12) : (1/3 	imes 12) : (1/4 	imes 12) = 6 : 4 : 3$.Let the sides be $6x, 4x,$ and $3x$.The perimeter of the triangle is the sum of its sides: $6x + 4x + 3x = 156$.$13x = 156$.$x = 156 / 13 = 12$.The largest side corresponds to the largest ratio part,which is $6x$.Largest side $= 6 	imes 12 = 72 	ext{ cm}$.

The sides of a triangle are in the ratio $1/2 : 1/3 : 1/4$ and its perimeter is $156 \text{ cm}$. The length of the largest side is (in $\text{cm}$):

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