The simplification of 1+frac{1}{2+frac{1}{1-f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To simplify the expression $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$,we solve from the bottom up.First,simplify the denominator of the lowest fracti

Vedclass · Accepted Answer

$\frac{9}{7}$

Vedclass · Answer

(C) To simplify the expression $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$,we solve from the bottom up.First,simplify the denominator of the lowest fraction: $1-\frac{1}{3} = \frac{3-1}{3} = \frac{2}{3}$.Now,the expression becomes $1+\frac{1}{2+\frac{1}{2/3}}$.Next,simplify the term $\frac{1}{2/3}$,which is $\frac{3}{2}$.Now,the expression becomes $1+\frac{1}{2+\frac{3}{2}}$.Simplify the denominator $2+\frac{3}{2} = \frac{4+3}{2} = \frac{7}{2}$.Finally,the expression becomes $1+\frac{1}{7/2} = 1+\frac{2}{7} = \frac{7+2}{7} = \frac{9}{7}$.

The simplification of $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$ yields the result

Similar Questions

What is the value of $\frac{(941+149)^{2}+(941-149)^{2}}{(941 \times 941+149 \times 149)}$?

If $2x + \frac{2}{x} = 1$,then the value of $x^{3} + \frac{1}{x^{3}}$ is

What should come in place of the question mark $(?)$ in the following equation?
$30.01^{2} - 19.98^{2} - ? = 21.81^{2}$

If $\frac{a^{2}+b^{2}}{c^{2}+d^{2}}=\frac{a b}{c d},$ then find the value of $\frac{a+b}{a-b}$ in terms of $c$ and $d$ only.

If the numbers $\sqrt[3]{9}, \sqrt[4]{20}, \sqrt[6]{25}$ are arranged in ascending order,then the correct arrangement is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module