What is the value of frac{(941+149)^{2}+(941- | vedclass

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(B) Let $a = 941$ and $b = 149$.The given expression is of the form $\frac{(a+b)^{2} + (a-b)^{2}}{a^{2} + b^{2}}$.Expanding the numerator using algebr

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) Let $a = 941$ and $b = 149$.The given expression is of the form $\frac{(a+b)^{2} + (a-b)^{2}}{a^{2} + b^{2}}$.Expanding the numerator using algebraic identities $(a+b)^{2} = a^{2} + b^{2} + 2ab$ and $(a-b)^{2} = a^{2} + b^{2} - 2ab$:Numerator $= (a^{2} + b^{2} + 2ab) + (a^{2} + b^{2} - 2ab) = 2(a^{2} + b^{2})$.Substituting this back into the expression:$\frac{2(a^{2} + b^{2})}{a^{2} + b^{2}} = 2$.Therefore,the value of the expression is $2$.

What is the value of $\frac{(941+149)^{2}+(941-149)^{2}}{(941 \times 941+149 \times 149)}$?

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