The sine of the angle between the straight line $\frac{x-2}{3}=\frac{3-y}{-4}=\frac{z-4}{5}$ and the plane $2x-2y+z=5$ is

  • A
    $\frac{3}{\sqrt{30}}$
  • B
    $\frac{3}{50}$
  • C
    $\frac{4}{5 \sqrt{2}}$
  • D
    $\frac{\sqrt{2}}{10}$

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