The size of isoelectronic species F^{-}, Ne a | vedclass

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(A) Isoelectronic species have the same number of electrons but different nuclear charges $(Z).$The size of isoelectronic species is primarily determi

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Nuclear charge $(Z)$

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(A) Isoelectronic species have the same number of electrons but different nuclear charges $(Z).$The size of isoelectronic species is primarily determined by the magnitude of the nuclear charge $(Z).$As the nuclear charge $(Z)$ increases,the force of attraction between the nucleus and the electrons increases,which pulls the electron cloud closer to the nucleus,resulting in a decrease in ionic/atomic size.For the given species:$F^{-} (Z=9), Ne (Z=10), Na^{+} (Z=11)$Since the nuclear charge increases from $F^{-}$ to $Na^{+},$ the size decreases in the order: $F^{-} > Ne > Na^{+}.$Thus,the size is affected by the nuclear charge $(Z).$

The size of isoelectronic species $F^{-},$ $Ne$ and $Na^{+}$ is affected by
$(a)$ Nuclear charge $(Z)$
$(b)$ Valence principal quantum number $(n)$
$(c)$ Electron-electron interaction in the outer orbitals
$(d)$ None of the factors because their size is the same.

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The size of isoelectronic species $F^{-},$ $Ne$ and $Na^{+}$ is affected by$(a)$ Nuclear charge $(Z)$$(b)$ Valence principal quantum number $(n)$$(c)$ Electron-electron interaction in the outer orbitals$(d)$ None of the factors because their size is the same.