The slope of the normal to the curve $x = \sqrt{t}$ and $y = t - \frac{1}{\sqrt{t}}$ at $t = 4$ is ...

  • A
    $-\frac{17}{4}$
  • B
    $\frac{4}{17}$
  • C
    $-\frac{4}{17}$
  • D
    $\frac{17}{4}$

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