The solubility of $AgCl$ is $1 \times 10^{-5} \ mol/L$. Its solubility in $0.1 \ M$ sodium chloride solution is

  • A
    $1 \times 10^{-10}$
  • B
    $1 \times 10^{-5}$
  • C
    $1 \times 10^{-9}$
  • D
    $1 \times 10^{-4}$

Explore More

Similar Questions

The molar solubility of $PbI_2$ in $0.2 \ M \ Pb(NO_3)_2$ solution in terms of solubility product of $PbI_2$ is

If the molar solubility (in $mol \cdot L^{-1}$) of a sparingly soluble salt $AB_4$ is $S$ and the corresponding solubility product is $K_{sp}$,then $S$ in terms of $K_{sp}$ is given by the relation:

The correct order of solubility of the given salts in water at $298 K$ is:
Salt$K_{sp}$ at $298 K$
$AgBr$$5.0 \times 10^{-13}$
$Zn(OH)_2$$1.0 \times 10^{-15}$
$Hg_2Cl_2$$1.3 \times 10^{-18}$

The $K_{sp}$ of $AgI$ is $1.5 \times 10^{-16}$. Which of the following mixtures of equal volumes will result in precipitation?

Difficult
View Solution

The solubility product of Lead sulphate,$PbSO_4$ is $1.3 \times 10^{-8}$. Calculate its solubility in pure water. The molecular mass of $PbSO_4 = 303 \ g \ mol^{-1}$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo