The solubility product of magnesium hydroxide | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For $Mg(OH)_2 \rightleftharpoons Mg^{2+} + 2OH^-$,the solubility product $K_{sp} = [Mg^{2+}][OH^-]^2 = (s)(2s)^2 = 4s^3$. In pure water: $4s^3 = 1

Vedclass · Accepted Answer

$1.44 	imes 10^{-4} \ M, 4.8 	imes 10^{-9} \ M$

Vedclass · Answer

(A) For $Mg(OH)_2 ightleftharpoons Mg^{2+} + 2OH^-$,the solubility product $K_{sp} = [Mg^{2+}][OH^-]^2 = (s)(2s)^2 = 4s^3$. In pure water: $4s^3 = 1.2 	imes 10^{-11} \implies s^3 = 0.3 	imes 10^{-11} = 3.0 	imes 10^{-12} \implies s = \sqrt[3]{3.0} 	imes 10^{-4} \approx 1.44 	imes 10^{-4} \ M$. In $0.05 \ M$ $NaOH$,$[OH^-] \approx 0.05 \ M$. $K_{sp} = [Mg^{2+}][OH^-]^2 \implies 1.2 	imes 10^{-11} = s(0.05)^2 \implies s = \frac{1.2 	imes 10^{-11}}{2.5 	imes 10^{-3}} = 4.8 	imes 10^{-9} \ M$.

The solubility product of magnesium hydroxide $Mg(OH)_2$ is $1.2 \times 10^{-11}$. Calculate its solubility in pure water and $0.05 \ M$ $NaOH$.

Similar Questions

The solubility product of $AgI$ at $25\,\text{°C}$ is $1.0 \times 10^{-16}\,\text{mol}^2\,\text{L}^{-2}$. The solubility of $AgI$ in $10^{-4}\,\text{N}$ solution of $KI$ at $25\,\text{°C}$ is approximately (in $\text{mol L}^{-1}$)

The solubility product of $Mg(OH)_2$ is $9 \times 10^{-12}$. If the concentration of $Mg^{+2}$ is $0.01 \ M$,then the concentration of $OH^{-}$ is = .....

Which of the following formulas can be used to calculate the solubility of $Ag_2CO_3$?

Which is the correct representation of the solubility product constant of $Ag_2CrO_4$?

At $T(K)$,the solubility product of $AgBr$ is $4 \times 10^{-13}$. What is its solubility in $0.1 \ M$ $KBr$ solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module