The solution of frac{dy}{dx} + sqrt{frac{1 - | vedclass

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(A) Given differential equation is $\frac{dy}{dx} + \sqrt{\frac{1 - y^2}{1 - x^2}} = 0$. Rearranging the terms,we get $\frac{dy}{dx} = -\frac{\sqrt{1

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$\sin^{-1} x + \sin^{-1} y = c$

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(A) Given differential equation is $\frac{dy}{dx} + \sqrt{\frac{1 - y^2}{1 - x^2}} = 0$. Rearranging the terms,we get $\frac{dy}{dx} = -\frac{\sqrt{1 - y^2}}{\sqrt{1 - x^2}}$. Separating the variables,we have $\frac{dy}{\sqrt{1 - y^2}} = -\frac{dx}{\sqrt{1 - x^2}}$. Integrating both sides,$\int \frac{dy}{\sqrt{1 - y^2}} = -\int \frac{dx}{\sqrt{1 - x^2}}$. This gives $\sin^{-1} y = -\sin^{-1} x + c$. Rearranging the terms,we get $\sin^{-1} x + \sin^{-1} y = c$.

The solution of $\frac{dy}{dx} + \sqrt{\frac{1 - y^2}{1 - x^2}} = 0$ is

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