The specific heat of argon at constant pressu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For an ideal gas,the relation between molar specific heats is $C_p - C_v = R$,where $R$ is the universal gas constant.Since $C_p$ and $C_v$ are gi

Vedclass · Accepted Answer

$\frac{P}{T(C_p-C_v)}$

Vedclass · Answer

(A) For an ideal gas,the relation between molar specific heats is $C_p - C_v = R$,where $R$ is the universal gas constant.Since $C_p$ and $C_v$ are given as specific heats (per unit mass),we use the relation $C_p - C_v = \frac{R}{M}$,where $M$ is the molar mass of the gas.Thus,$R = M(C_p - C_v)$.The ideal gas equation is $PV = nRT$,where $n = \frac{m}{M}$ is the number of moles.Substituting $n$ and $R$ into the equation: $PV = \frac{m}{M} \cdot M(C_p - C_v) \cdot T$.Simplifying,we get $PV = m(C_p - C_v)T$.Since density $\rho = \frac{m}{V}$,we can rewrite the equation as $P = \frac{m}{V}(C_p - C_v)T$.Therefore,$\rho = \frac{P}{(C_p - C_v)T}$.

The specific heat of argon at constant pressure and constant volume are $C_p$ and $C_v$ respectively. Its density $\rho$ at $N.T.P.$ will be: [Where $P$ and $T$ are pressure and temperature respectively at $N.T.P.$]

Similar Questions

For a gas,$\frac{R}{C_{V}} = 0.4$,where $R$ is the universal gas constant and $C_{V}$ is the molar specific heat at constant volume. The gas is made up of molecules which are

Which of the following statements is correct regarding the molar specific heat of $1$ mole of an ideal gas at constant pressure $(C_P)$ and constant volume $(C_V)$?

Identify the correct relationship between the molar heat capacities of an ideal gas.

$A$ triatomic,diatomic,and monatomic gas are supplied the same amount of heat at constant pressure. Then:

In gases of diatomic molecules,the ratio of the two specific heats of gases ${C_P}/{C_V}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module