The speed of an electron having a wavelength | vedclass

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(A) The de Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{p} = \frac{h}{mv}$.Rearranging for velocity $v$,we get $v = \frac{

Vedclass · Accepted Answer

$7.25$

Vedclass · Answer

(A) The de Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{p} = \frac{h}{mv}$.Rearranging for velocity $v$,we get $v = \frac{h}{m\lambda}$.Substituting the values: $h = 6.63 	imes 10^{-34} \ J \cdot s$,$m = 9.11 	imes 10^{-31} \ kg$,and $\lambda = 10^{-10} \ m$.$v = \frac{6.63 	imes 10^{-34}}{(9.11 	imes 10^{-31}) 	imes (10^{-10})} = \frac{6.63}{9.11} 	imes 10^{7} \ m/s \approx 0.727 	imes 10^{7} \ m/s = 7.27 	imes 10^6 \ m/s$.Rounding to the nearest provided option,the speed is $7.25 	imes 10^6 \ m/s$.

The speed of an electron having a wavelength of $10^{-10} \ m$ is ........... $\times 10^6 \ m/s$.

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