The spin-only magnetic moment of the complex | vedclass

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Question

(D) Fehling's reagent contains a complex of $Cu^{2+}$ ions,specifically copper$(II)$ tartrate.The electronic configuration of $Cu^{2+}$ is $[Ar] 3d^9$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(D) Fehling's reagent contains a complex of $Cu^{2+}$ ions,specifically copper$(II)$ tartrate.The electronic configuration of $Cu^{2+}$ is $[Ar] 3d^9$.In a $3d^9$ configuration,there is $1$ unpaired electron.The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.$\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ B.M.$The nearest integer to $1.73$ is $2$.

Complexes	No. of unpaired electrons
$A. [CrF_6]^{4-}$	$P. 5$
$B. [MnF_6]^{4-}$	$Q. 2$
$C. [Cr(CN)_6]^{4-}$	$R. 1$
$D. [Mn(CN)_6]^{4-}$	$S. 4$

The spin-only magnetic moment of the complex present in Fehling's reagent is $B.M.$ (Nearest integer).

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