The statement $(p \wedge (\sim q)) \vee ((\sim p) \wedge q) \vee ((\sim p) \wedge (\sim q))$ is equivalent to

$p \Rightarrow q$ can also be written as

Consider the following statements:
Statement $I$: If a quadrilateral $ABCD$ is a square,then all of its sides are equal.
Statement $II$: If all the sides of a quadrilateral $ABCD$ are equal,then $ABCD$ is a square.
Then:

If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is $False$, then the truth values of $p \to q$ and $q \to p$ are respectively......

The simplified switching circuit for the following circuit is (Assume the circuit consists of two switches $S_1$ and $S_2$ in parallel, connected in series with a switch $S_3$):

Check whether the following statement is true or not.
If $x, y \in \mathbb{Z}$ are such that $x$ and $y$ are odd,then $xy$ is odd.