If the truth value of the compound statement | vedclass

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(C) The implication $A 	o B$ is $False$ only when $A$ is $True$ and $B$ is $False$.Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r)]$ and $B = (

Vedclass · Accepted Answer

$(F, T)$

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(C) The implication $A 	o B$ is $False$ only when $A$ is $True$ and $B$ is $False$.Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r)]$ and $B = (p \land q)$.Since $B$ is $False$, $(p \land q) = False$.Since $A$ is $True$, $(p \lor q) = True$, $(q 	o r) = True$, and $(\sim r) = True$.From $(\sim r) = True$, we get $r = False$.Substitute $r = False$ into $(q 	o r) = True$: $(q 	o False) = True$, which implies $q = False$.Substitute $q = False$ into $(p \lor q) = True$: $(p \lor False) = True$, which implies $p = True$.Now, check $(p \land q) = (True \land False) = False$, which matches our condition.Thus, $p = True$ and $q = False$.Then, $p 	o q = (True 	o False) = False$.And $q 	o p = (False 	o True) = True$.The truth values are $(F, T)$.

If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is $False$, then the truth values of $p \to q$ and $q \to p$ are respectively......

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