The statement pattern (p wedge q) to (r vee s | vedclass

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(B) $1$. An implication $A 	o B$ is false only when $A$ is true and $B$ is false.$2$. Here, $A = (p \wedge q)$ and $B = (r \vee \sim s)$.$3$. For $(p

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$T$, $T$, $F$, $T$

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(B) $1$. An implication $A 	o B$ is false only when $A$ is true and $B$ is false.$2$. Here, $A = (p \wedge q)$ and $B = (r \vee \sim s)$.$3$. For $(p \wedge q)$ to be true, both $p$ and $q$ must be true $(T)$.$4$. For $(r \vee \sim s)$ to be false, both $r$ and $\sim s$ must be false $(F)$.$5$. If $r$ is false $(F)$ and $\sim s$ is false $(F)$, then $s$ must be true $(T)$.$6$. Thus, the truth values are $p=T, q=T, r=F, s=T$.

The statement pattern $(p \wedge q) \to (r \vee \sim s)$ is false. Then the truth values of $p, q, r$ and $s$ are respectively

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