The straight line passing through (-3, 6) and | vedclass

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(D) Step $1$: Find the midpoint $M$ of the line segment joining $(4, -5)$ and $(-2, 9)$.$M = (\frac{4 + (-2)}{2}, \frac{-5 + 9}{2}) = (\frac{2}{2}, \f

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$\frac{3\pi}{4}$

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(D) Step $1$: Find the midpoint $M$ of the line segment joining $(4, -5)$ and $(-2, 9)$.$M = (\frac{4 + (-2)}{2}, \frac{-5 + 9}{2}) = (\frac{2}{2}, \frac{4}{2}) = (1, 2)$.Step $2$: Find the slope $m$ of the line passing through $(-3, 6)$ and $(1, 2)$.$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 6}{1 - (-3)} = \frac{-4}{4} = -1$.Step $3$: Find the inclination $	heta$.Since $m = 	an(	heta) = -1$,and $0 \le 	heta < \pi$,we have $	heta = \pi - \frac{\pi}{4} = \frac{3\pi}{4}$.

The straight line passing through $(-3, 6)$ and the midpoint of the line segment joining the points $(4, -5)$ and $(-2, 9)$ has an inclination of:

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