The points A(-a, -b),B(0, 0),C(a, b),and D(a^ | vedclass

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(A) To check if the points are collinear,we can check the slopes of the line segments formed by these points.Slope of $AB = \frac{0 - (-b)}{0 - (-a)}

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(A) To check if the points are collinear,we can check the slopes of the line segments formed by these points.Slope of $AB = \frac{0 - (-b)}{0 - (-a)} = \frac{b}{a}$.Slope of $BC = \frac{b - 0}{a - 0} = \frac{b}{a}$.Since the slope of $AB$ is equal to the slope of $BC$,the points $A, B,$ and $C$ are collinear.Now,check the slope of $CD = \frac{ab - b}{a^2 - a} = \frac{b(a - 1)}{a(a - 1)} = \frac{b}{a}$ (for $a 
eq 1, a 
eq 0$).Since the slope of $BC$ is equal to the slope of $CD$,the points $B, C,$ and $D$ are also collinear.Since all points lie on the same line with slope $\frac{b}{a}$,the points $A, B, C,$ and $D$ are collinear.

The points $A(-a, -b)$,$B(0, 0)$,$C(a, b)$,and $D(a^2, ab)$ are

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