The sum of coefficients in (1 + x - 3x^2)^{21 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the sum of the coefficients of a polynomial $P(x)$,we substitute $x = 1$ into the expression.Given the expression $P(x) = (1 + x - 3x^2)^{

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) To find the sum of the coefficients of a polynomial $P(x)$,we substitute $x = 1$ into the expression.Given the expression $P(x) = (1 + x - 3x^2)^{2134}$.Substituting $x = 1$:$P(1) = (1 + 1 - 3(1)^2)^{2134}$$P(1) = (1 + 1 - 3)^{2134}$$P(1) = (-1)^{2134}$Since $2134$ is an even number,$(-1)^{2134} = 1$.Therefore,the sum of the coefficients is $1$.

The sum of coefficients in $(1 + x - 3x^2)^{2134}$ is

Similar Questions

The sum of the coefficients in the expansion of $(1+x+x^2)^n$ is

Which is larger: $(1.01)^{1000000}$ or $10,000$?

For $|x| < \frac{1}{5}$,the coefficient of $x^3$ in the expansion of $\frac{1}{(1-5 x)(1-4 x)}$ is

Find the coefficient of $x^5$ in $(1+x+x^2)^8$.

The number of terms in the expansion of $(a + b + c)^n$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module