The symbolic form of the following circuit is (where $p, q$ and $r$ represent switches $s_{1}, s_{2}$ and $s_{3}$ which are closed respectively):
- A$(p \wedge q) \vee [\sim p \wedge (\sim q \vee p \vee r)] \equiv \ell$
- B$[(p \vee q) \wedge \sim p] \vee [\sim p \vee q \vee r] \equiv \ell$
- C$(p \wedge q) \vee [\sim p \wedge (\sim q \vee p \vee r)] \equiv \ell$
- D$(p \wedge q) \vee \sim p \vee [\sim p \vee p \vee r] \equiv \ell$
Explore More
Similar Questions
The statement $(p$ $\rightarrow (q$ $\rightarrow p))$ $\rightarrow (p$ $\rightarrow (p \vee q))$ is
Let $a: \sim(p \wedge \sim r) \vee(\sim q \vee s)$ and $b: (p \vee s) \leftrightarrow(q \wedge r)$. If the truth values of $p$ and $q$ are $T$ and that of $r$ and $s$ are $F$,then the truth values of $a$ and $b$ are respectively...
For the statements $p$ and $q$,consider the following compound statements :
$(a)$ $(\sim q \wedge (p$ $\rightarrow q))$ $\rightarrow \sim p$
$(b)$ $((p \vee q) \wedge \sim p) \rightarrow q$
Then which of the following statements is correct?
$(a)$ $(\sim q \wedge (p$ $\rightarrow q))$ $\rightarrow \sim p$
$(b)$ $((p \vee q) \wedge \sim p) \rightarrow q$
Then which of the following statements is correct?
If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is false, then the truth values of $p \to q$ and $q \to p$ are respectively...
DifficultMHT CET 2026
View SolutionThe negation of $p \wedge (q \rightarrow r)$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo