The system of linear equations ax - y + 2 = 0 | vedclass

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(A) The given system of linear equations is:$ax - y = -2$$x + ay = -3$For a system of linear equations $a_1x + b_1y = c_1$ and $a_2x + b_2y = c_2$ to

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$R$

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(A) The given system of linear equations is:$ax - y = -2$$x + ay = -3$For a system of linear equations $a_1x + b_1y = c_1$ and $a_2x + b_2y = c_2$ to have a unique solution,the condition is $\frac{a_1}{a_2} 
eq \frac{b_1}{b_2}$.Here,$a_1 = a$,$b_1 = -1$,$a_2 = 1$,and $b_2 = a$.Substituting these values into the condition:$\frac{a}{1} 
eq \frac{-1}{a}$$a^2 
eq -1$Since $a^2$ is always non-negative for any real number $a$,$a^2$ can never be equal to $-1$.Therefore,the condition $a^2 
eq -1$ is satisfied for all real numbers $a$.Thus,the set of values of $a$ is $R$.

The system of linear equations $ax - y + 2 = 0$ and $x + ay + 3 = 0$ has a unique solution. Then,the set of values of $a$ is . . . . . . .

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