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(C) $4.25 	ext{ g}$ $NH_3 = (4.25 / 17) 	imes 4 	imes N_A = 1 	imes N_A$ atoms.$(B)$ $8 	ext{ g}$ $O_2 = (8 / 32) 	imes 2 	imes N_A = 0.5 	ime

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$2 	ext{ g}$ $H_2$

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(C) $4.25 	ext{ g}$ $NH_3 = (4.25 / 17) 	imes 4 	imes N_A = 1 	imes N_A$ atoms.$(B)$ $8 	ext{ g}$ $O_2 = (8 / 32) 	imes 2 	imes N_A = 0.5 	imes N_A$ atoms.$(C)$ $2 	ext{ g}$ $H_2 = (2 / 2) 	imes 2 	imes N_A = 2 	imes N_A$ atoms.$(D)$ $4 	ext{ g}$ $He = (4 / 4) 	imes 1 	imes N_A = 1 	imes N_A$ atoms.Comparing the values, $2 	ext{ g}$ $H_2$ contains the maximum number of atoms.

The system that contains the maximum number of atoms is

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