The term independent of $x$ in the expansion of $\left( 9x - \frac{1}{3\sqrt{x}} \right)^{18}, x > 0$,is $\alpha$ times the corresponding binomial coefficient. Then $\alpha$ is:

  • A
    $3$
  • B
    $\frac{1}{3}$
  • C
    $-\frac{1}{3}$
  • D
    $1$

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