The three straight lines $ax + by = c$,$bx + cy = a$ and $cx + ay = b$ are concurrent,if

If the three lines $p_1x + q_1y = 1$,$p_2x + q_2y = 1$,and $p_3x + q_3y = 1$ are concurrent,then the points $(p_1, q_1)$,$(p_2, q_2)$,and $(p_3, q_3)$ are:

The family of straight lines $4ax + 3by + c = 0$ such that $a + b + c = 0$ (where $a, b, c$ are real constants) are concurrent at the point...

Let $\alpha, \beta, \gamma$ be three non-zero real constants and $a, b, c$ be three arbitrary real numbers which satisfy $\alpha a + \beta b + \gamma c = 0$. Then the point of concurrence of the family of lines $ax + by + c = 0$ is

What is the equation of the line passing through the intersection of the lines $3x - 4y + 1 = 0$ and $5x + y - 1 = 0$ and having equal intercepts on the axes?

If the lines $x+2ay+a=0$,$x+3by+b=0$,and $x+4cy+c=0$ are concurrent,then $a, b$,and $c$ are in