The threshold frequency for a certain metal is $v_0$. When radiation of frequency $2v_0$ is incident on this metal surface,the maximum velocity of the emitted photoelectrons is $2 \times 10^6 \ m/s$. If radiation of frequency $3v_0$ is incident on the same metal surface,the maximum velocity of the emitted photoelectrons is . . . . . .

  • A
    $\sqrt{2} \times 10^6 \ m/s$
  • B
    $2\sqrt{2} \times 10^6 \ m/s$
  • C
    $4 \times 10^6 \ m/s$
  • D
    $5 \times 10^6 \ m/s$

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The figure shows the plot of stopping potential $(V_0)$ versus $(1/\lambda)$ for three different metals. If $\phi$ is the work function,then which of the following is correct?

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