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(B) satellite with a time period equal to the rotation of the Earth $(T = 24 \,h)$ is a geostationary satellite.For a geostationary satellite,the orbi

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$35,840 \,km$

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(B) satellite with a time period equal to the rotation of the Earth $(T = 24 \,h)$ is a geostationary satellite.For a geostationary satellite,the orbital radius $r$ is given by $r = \left( \frac{T^2 GM_e}{4 \pi^2} ight)^{1/3}$.Substituting the values $T = 86,400 \,s$,$G = 6.67 	imes 10^{-11} \,Nm^2/kg^2$,and $M_e = 5.97 	imes 10^{24} \,kg$,we get $r \approx 42,200 \,km$.The altitude $h$ is given by $h = r - R_e$,where $R_e \approx 6,400 \,km$.Thus,$h = 42,200 \,km - 6,400 \,km = 35,800 \,km$.Therefore,the altitude is nearly $35,840 \,km$.

The time period of a $1500 \,kg$ satellite is equal to the time period of rotation of the earth. The altitude of the satellite is nearly

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