The total energy of a satellite in a circular | vedclass

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Question

(A) The total energy $(E)$ of a satellite in a circular orbit is given by the formula:$E = -\frac{GMm}{2r}$Where:- $G$ is the universal gravitational

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$-\frac{1}{(R+h)}$

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(A) The total energy $(E)$ of a satellite in a circular orbit is given by the formula:$E = -\frac{GMm}{2r}$Where:- $G$ is the universal gravitational constant.- $M$ is the mass of the Earth.- $m$ is the mass of the satellite.- $r = R + h$ is the distance from the center of the Earth.Substituting $r = R + h$ into the energy equation,we get:$E = -\frac{GMm}{2(R+h)}$Since $G, M, m,$ and $2$ are constants,the total energy $E$ is proportional to $-\frac{1}{R+h}$.Thus,the total energy varies as $-\frac{1}{R+h}$.

The total energy of a satellite in a circular orbit at a distance $(R+h)$ from the centre of the Earth varies as [ $R$ is the radius of the Earth and $h$ is the height of the orbit from Earth's surface].

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