The total maximum transmitted power in amplit | vedclass

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Question

(A) The total transmitted power $P_t$ in amplitude modulation is given by the formula: $P_t = P_c (1 + \frac{\mu^2}{2})$,where $P_c$ is the carrier po

Vedclass · Accepted Answer

$1.5 \ kW$

Vedclass · Answer

(A) The total transmitted power $P_t$ in amplitude modulation is given by the formula: $P_t = P_c (1 + \frac{\mu^2}{2})$,where $P_c$ is the carrier power and $\mu$ is the modulation index.For maximum transmitted power,the modulation index $\mu$ must be at its maximum value,which is $1$.Given,$P_c = 1 \ kW$ and $\mu = 1$.Substituting these values into the formula:$P_t = 1 \ kW 	imes (1 + \frac{1^2}{2})$$P_t = 1 \ kW 	imes (1 + 0.5)$$P_t = 1.5 \ kW$.Therefore,the total maximum transmitted power is $1.5 \ kW$.

List $I$	List $II$
$A$. Attenuation	$I$. Combination of a receiver and transmitter.
$B$. Transducer	$II$. Process of retrieval of information from the carrier wave at receiver.
$C$. Demodulation	$III$. Converts one form of energy into another.
$D$. Repeater	$IV$. Loss of strength of a signal while propagating through a medium.

The total maximum transmitted power in amplitude modulation if the carrier output power is $1 \ kW$ is

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