The total number of 4-digit numbers whose gre | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $N$ be a $4$-digit number. We are given $\gcd(N, 54) = 2$.Since $54 = 2 	imes 3^3$,the condition $\gcd(N, 54) = 2$ implies that $N$ must be d

Vedclass · Accepted Answer

$3000$

Vedclass · Answer

(A) Let $N$ be a $4$-digit number. We are given $\gcd(N, 54) = 2$.Since $54 = 2 	imes 3^3$,the condition $\gcd(N, 54) = 2$ implies that $N$ must be divisible by $2$ but not by $3$.Total $4$-digit numbers range from $1000$ to $9999$,so there are $9000$ such numbers.Number of $4$-digit numbers divisible by $2$ is $\lfloor \frac{9999}{2} floor - \lfloor \frac{999}{2} floor = 4999 - 499 = 4500$.Number of $4$-digit numbers divisible by $6$ (i.e.,divisible by both $2$ and $3$) is $\lfloor \frac{9999}{6} floor - \lfloor \frac{999}{6} floor = 1666 - 166 = 1500$.The number of $4$-digit numbers divisible by $2$ but not by $3$ is $4500 - 1500 = 3000$.

The total number of $4$-digit numbers whose greatest common divisor with $54$ is $2$ is $..........$.

Similar Questions

The largest non-negative integer $k$ such that $24^k$ divides $13!$ is

The number of $3$-digit numbers that are divisible by $2$ and $3$,but not divisible by $4$ and $9$,is

The number of positive divisors of $252$ is

The exponent of $6$ in $72!$ is

Total number of divisors of $480$ that are of the form $4n + 2$,where $n \geq 0$,is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module