The total number of hydrogen atoms in product | vedclass

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(C) The reaction of $CH_3CH_2Br$ with $NaOH$ in the presence of $C_2H_5OH$ (alcoholic $NaOH$) undergoes dehydrohalogenation to form ethene $(CH_2=CH_2

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$10$

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(C) The reaction of $CH_3CH_2Br$ with $NaOH$ in the presence of $C_2H_5OH$ (alcoholic $NaOH$) undergoes dehydrohalogenation to form ethene $(CH_2=CH_2)$ as product $A$.Product $A$ has $4$ hydrogen atoms.The reaction of $CH_3CH_2Br$ with $NaOH$ in the presence of $H_2O$ (aqueous $NaOH$) undergoes nucleophilic substitution to form ethanol $(CH_3CH_2OH)$ as product $B$.Product $B$ has $6$ hydrogen atoms.The total number of hydrogen atoms in product $A$ and product $B$ is $4 + 6 = 10$.

The total number of hydrogen atoms in product $A$ and product $B$ is $ . . . . . . $.

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