The total power dissipated (in $watt$) in the circuit shown is

Let there be $n$ resistors $R_1, \dots, R_n$ with $R_{\max} = \max \{R_1, \dots, R_n\}$ and $R_{\min} = \min \{R_1, \dots, R_n\}$. Show that when they are connected in parallel,the resultant resistance $R_p < R_{\min}$ and when they are connected in series,the resultant resistance $R_s > R_{\max}$. Interpret the result physically.

The total current supplied to the circuit by the battery is . . . . . . . (in $A$)

$A$ uniform conductor of resistance $R$ is cut into $20$ equal pieces. Half of them are joined in series and the remaining half of them are connected in parallel. If the two combinations are joined in series,the effective resistance of all the pieces is

When two conducting wires are connected in series,the equivalent resistance is $14\, \Omega$,and when they are connected in parallel,the equivalent resistance is $3.43\, \Omega$. The resistance of the wire with the higher value is ................. $\Omega$.

The equivalent resistance of a series combination of two resistors is $s$. When they are connected in parallel,the equivalent resistance is $p$. If $s = np$,then the minimum value for $n$ is (Round off to the nearest integer).