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(D) The sides of the triangular side walls of the flyover are $a = 13 \, m$,$b = 14 \, m$,and $c = 15 \, m$.First,we calculate the semi-perimeter $s$:

Vedclass · Accepted Answer

$84000$

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(D) The sides of the triangular side walls of the flyover are $a = 13 \, m$,$b = 14 \, m$,and $c = 15 \, m$.First,we calculate the semi-perimeter $s$:$s = \frac{a + b + c}{2} = \frac{13 + 14 + 15}{2} = \frac{42}{2} = 21 \, m$.Using Heron's formula,the area of the triangle is:$	ext{Area} = \sqrt{s(s - a)(s - b)(s - c)} = \sqrt{21(21 - 13)(21 - 14)(21 - 15)}$$= \sqrt{21 	imes 8 	imes 7 	imes 6} = \sqrt{(3 	imes 7) 	imes (2^3) 	imes 7 	imes (2 	imes 3)}$$= \sqrt{7^2 	imes 3^2 	imes 2^4} = 7 	imes 3 	imes 2^2 = 84 \, m^2$.The annual rent is $Rs \, 2000$ per $m^2$.The rent for $1 \, m^2$ for $6$ months (half a year) is $Rs \, \frac{2000}{2} = Rs \, 1000$.Therefore,the total rent for $84 \, m^2$ for $6$ months is $84 	imes 1000 = Rs \, 84,000$.

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are $13 \, m$,$14 \, m$,and $15 \, m$. The advertisements yield an earning of $Rs \, 2000$ per $m^2$ a year. $A$ company hired one of its walls for $6$ months. How much rent did it pay? (in $Rs$)

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