(C) According to Heisenberg's uncertainty principle,$\Delta x \times \Delta p \geq \frac{h}{4\pi}$.Given $\Delta p = 1 \times 10^{-5} \ kg \ m/s$ and

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(C) According to Heisenberg's uncertainty principle,$\Delta x \times \Delta p \geq \frac{h}{4\pi}$.Given $\Delta p = 1 \times 10^{-5} \ kg \ m/s$ and $h = 6.62 \times 10^{-34} \ kg \ m^2/s$.Substituting the values: $\Delta x = \frac{h}{4\pi \times \Delta p}$.$\Delta x = \frac{6.62 \times 10^{-34}}{4 \times 3.14159 \times 1 \times 10^{-5}}$.$\Delta x = \frac{6.62 \times 10^{-34}}{12.566 \times 10^{-5}} \approx 5.27 \times 10^{-30} \ m$.

Class 11 Chemistry Structure of Atom Uncertainty principle and Schrodinger wave equation

Medium

The uncertainty in momentum of an electron is $1 \times 10^{-5} \ kg \ m/s$. The uncertainty in its position will be $(h = 6.62 \times 10^{-34} \ kg \ m^2/s)$

AIPMT 1999 All AIPMT

A
$1.05 \times 10^{-28} \ m$
B
$1.05 \times 10^{-26} \ m$
C
$5.27 \times 10^{-30} \ m$
D
$5.25 \times 10^{-28} \ m$

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Structure of Atom

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Uncertainty principle and Schrodinger wave equation

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The uncertainty in momentum of an electron is $1 \times 10^{-5} \ kg \ m/s$. The uncertainty in its position will be $(h = 6.62 \times 10^{-34} \ kg \ m^2/s)$

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