The unit of absolute permittivity is

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(B) The formula for the capacitance of a parallel plate capacitor is $C = \frac{\epsilon A}{d}$,where $\epsilon$ is the absolute permittivity,$A$ is t

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$F \cdot m^{-1}$

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(B) The formula for the capacitance of a parallel plate capacitor is $C = \frac{\epsilon A}{d}$,where $\epsilon$ is the absolute permittivity,$A$ is the area,and $d$ is the distance between plates.Rearranging for $\epsilon$,we get $\epsilon = \frac{C \cdot d}{A}$.The unit of capacitance $C$ is Farad $(F)$,the unit of distance $d$ is meter $(m)$,and the unit of area $A$ is square meter $(m^2)$.Substituting these units: $	ext{Unit of } \epsilon = \frac{F \cdot m}{m^2} = F \cdot m^{-1}$.Therefore,the unit of absolute permittivity is $F \cdot m^{-1}$.

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