The unit of mobility in terms of fundamental | vedclass

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(C) Mobility $\mu$ is defined as the ratio of drift velocity $v_d$ to the electric field $E$: $\mu = \frac{v_d}{E}$.The unit of drift velocity $v_d$ i

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$kg^{-1} s^2 A$

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(C) Mobility $\mu$ is defined as the ratio of drift velocity $v_d$ to the electric field $E$: $\mu = \frac{v_d}{E}$.The unit of drift velocity $v_d$ is $m/s$.The unit of electric field $E$ is $N/C$ (or $V/m$).Substituting the fundamental units:$1 \ N = 1 \ kg \cdot m/s^2$$1 \ C = 1 \ A \cdot s$Therefore,the unit of $E$ is $\frac{kg \cdot m/s^2}{A \cdot s} = \frac{kg \cdot m}{A \cdot s^3}$.Now,calculating the unit of $\mu$:$\mu = \frac{m/s}{kg \cdot m / (A \cdot s^3)} = \frac{m}{s} \cdot \frac{A \cdot s^3}{kg \cdot m} = \frac{A \cdot s^2}{kg} = kg^{-1} s^2 A$.Thus,the correct option is $C$.

The unit of mobility in terms of fundamental units is . . . . . . .

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