The value of 4-frac{5}{1+frac{1}{3+frac{1}{2+ | vedclass

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(D) To solve the expression $4-\frac{5}{1+\frac{1}{3+\frac{1}{2+\frac{1}{4}}}}$,we simplify from the bottom up.First,simplify the lowest fraction: $2+

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$\frac{1}{8}$

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(D) To solve the expression $4-\frac{5}{1+\frac{1}{3+\frac{1}{2+\frac{1}{4}}}}$,we simplify from the bottom up.First,simplify the lowest fraction: $2+\frac{1}{4} = \frac{8+1}{4} = \frac{9}{4}$.Next,substitute this back: $3+\frac{1}{9/4} = 3+\frac{4}{9} = \frac{27+4}{9} = \frac{31}{9}$.Then,substitute this back: $1+\frac{1}{31/9} = 1+\frac{9}{31} = \frac{31+9}{31} = \frac{40}{31}$.Finally,substitute this into the main expression: $4-\frac{5}{40/31} = 4-\frac{5 	imes 31}{40} = 4-\frac{155}{40} = 4-\frac{31}{8}$.Calculating the final value: $\frac{32-31}{8} = \frac{1}{8}$.

The value of $4-\frac{5}{1+\frac{1}{3+\frac{1}{2+\frac{1}{4}}}}$ is:

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