The value of $\sum \limits_{n=0}^{1947} \frac{1}{2^n+\sqrt{2^{1947}}}$ is equal to

  • A
    $\frac{487}{\sqrt{2^{1945}}}$
  • B
    $\frac{1946}{\sqrt{2^{1947}}}$
  • C
    $\frac{1947}{\sqrt{2^{1947}}}$
  • D
    $\frac{1948}{\sqrt{2^{1947}}}$

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