The value of int cot x , dx is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) We know that $\cot x = \frac{\cos x}{\sin x}$.Therefore,$\int \cot x \, dx = \int \frac{\cos x}{\sin x} \, dx$.Let $u = \sin x$,then $du = \cos x

Vedclass · Accepted Answer

$\log |\sin x| + c$

Vedclass · Answer

(C) We know that $\cot x = \frac{\cos x}{\sin x}$.Therefore,$\int \cot x \, dx = \int \frac{\cos x}{\sin x} \, dx$.Let $u = \sin x$,then $du = \cos x \, dx$.Substituting these into the integral,we get $\int \frac{1}{u} \, du = \log |u| + c$.Substituting back $u = \sin x$,we obtain $\log |\sin x| + c$.

The value of $\int \cot x \, dx$ is

Similar Questions

$\int \frac{dx}{\cos(x - a)\cos(x - b)} = $

Integrate the function: $\sqrt{1+\frac{x^{2}}{9}}$

$\int \frac{x+\sin x}{1+\cos x} d x=$

The value of $\int {\frac{1}{{{{(x - 5)}^2}}}\,dx} $ is

$\int \frac{2x}{(2x + 1)^2} dx = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module