The value of acceleration due to gravity

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The Earth is not a perfect sphere; it is flattened at the poles and bulges at the equator. As a result,the distance from the center of the Earth t

Vedclass · Accepted Answer

is least on equator

Vedclass · Answer

(B) The Earth is not a perfect sphere; it is flattened at the poles and bulges at the equator. As a result,the distance from the center of the Earth to the surface is greater at the equator than at the poles. The formula for acceleration due to gravity is $g = \frac{GM}{R^2}$,where $g$ is inversely proportional to the square of the radius $(R)$. Since the radius $R$ is largest at the equator,the value of $g$ is least at the equator.

Similar Questions

The law of gravitation gives the gravitational force between:

On Earth,how much force is needed to lift an object of mass $100 \,g$ (in $,N$)?

Identical packets are dropped from two aeroplanes,one above the equator and the other above the north pole,both at height $h$. Assuming all conditions are identical,will those packets take the same time to reach the surface of the Earth? Justify your answer.

What would be the effect on the weight of a body if the earth stopped rotating?

Explain an activity to show that,during a free fall,heavier and lighter objects accelerate at the same rate.

Vedclass Test Series

Exam Paper Generator

Online Exam Module