The value of plate current $I_P$ in the given circuit diagram will be in $mA$.

The value of the amplification factor from the following graph is:

Before the saturation state of a diode,at plate voltages of $400 \, V$ and $200 \, V$,the currents are $i_1$ and $i_2$ respectively. The ratio $i_1/i_2$ will be:

$14 \times 10^{15}$ electrons reach the anode per second. If the power consumed is $448 \text{ mW}$,then the plate (anode) voltage is .... $V$.

In a triode valve,the amplification factor is $20$ and the mutual conductance is $10^{-3} \text{ mho}$. The plate resistance is:

If the amplification factor of a triode $(\mu)$ is $22$ and its plate resistance is $6600 \, \Omega$,then the mutual conductance of this valve in mho is: