The vapour pressure of a solvent $A$ is $0.80 \, atm$. When a non-volatile substance $B$ is added to this solvent its vapour pressure drops to $0.6 \, atm$. What is the mole fraction of $B$ in the solution?

Relative lowering in vapour pressure of a solution containing a non-volatile solute is the ratio of:

Assume that acetone and water form an ideal solution. If $174 \ g$ of acetone $(CH_3COCH_3)$ is mixed with $126 \ g$ of $H_2O$,what is the vapour pressure of the solution at $298 \ K$? Given that ${P^0}_{acetone} = 360 \ torr$ and ${P^0}_{H_2O} = 24 \ torr$ at $298 \ K$.

Calculate the weight of non-volatile solute having molecular weight $40$,which is dissolved in $57 \ g$ octane to reduce its vapour pressure by $20\%$.

$6 \ g$ of a non-volatile solute $(x)$ is dissolved in $100 \ g$ of water. The relative lowering of vapour pressure of the resultant solution is $0.006$. What is the molar mass (in $g \ mol^{-1}$) of $x$?

For two components $A$ and $B$,$P_A^0 : P_B^0 = 1:2$ and $X_A : X_B = 1:2$. The mole fraction of $A$ in the vapor phase is: