The variation of the resistance of a conductor with temperature is as shown in the graph. The temperature coefficient $(\alpha)$ of the conductor is:
- A$ \frac{R_{0}}{m} $
- B$ mR_{0} $
- C$ m^{2} R_{0} $
- D$ \frac{m}{R_{0}} $
Explore More
Similar Questions
$A$ wire of resistance $R$ is stretched until its radius is halved. What will be the new resistance (in $, R$)?
Difficult
View SolutionIf $n, e, \tau$ and $m$ represent electron density,charge,relaxation time,and mass of an electron respectively,then the resistance of a wire of length $l$ and cross-sectional area $A$ is given by:
Easy
View Solution$A$ silver wire has a resistance of $2.1 \Omega$ at $27.5^{\circ} C$ and a resistance of $2.7 \Omega$ at $100^{\circ} C$. Then the temperature coefficient of the resistivity of silver will be . . . . . . .
$A$ given piece of wire of length $l$ and radius $r$ and resistance $R$ is stretched uniformly to a wire of radius $\frac{r}{2}$. Its new resistance is .................. $R$.
Difficult
View SolutionThe resistance of a wire is $R \; \Omega$. If it is melted and stretched to $n$ times its original length,its new resistance will be
MediumNEET 2017
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo