The vector sum of two forces is perpendicular | vedclass

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(A) If two vectors are perpendicular,their dot product must be equal to zero.According to the problem:$(\overrightarrow{A} + \overrightarrow{B}) \cdot

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Are equal to each other in magnitude

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(A) If two vectors are perpendicular,their dot product must be equal to zero.According to the problem:$(\overrightarrow{A} + \overrightarrow{B}) \cdot (\overrightarrow{A} - \overrightarrow{B}) = 0$$\Rightarrow \overrightarrow{A} \cdot \overrightarrow{A} - \overrightarrow{A} \cdot \overrightarrow{B} + \overrightarrow{B} \cdot \overrightarrow{A} - \overrightarrow{B} \cdot \overrightarrow{B} = 0$Since the dot product is commutative,$\overrightarrow{A} \cdot \overrightarrow{B} = \overrightarrow{B} \cdot \overrightarrow{A}$,so the middle terms cancel out:$\Rightarrow A^2 - B^2 = 0$$\Rightarrow A^2 = B^2$$	herefore A = B$This means the two forces are equal to each other in magnitude.

The vector sum of two forces is perpendicular to their vector difference. In that case,the forces

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