The velocity of a particle is given by $v = 2t^2 - 8t + 15 \,ms^{-1}$. Find its instantaneous acceleration at $t = 5 \,s$. (in $\,ms^{-2}$)

The acceleration at the end of $2 \ s$ of a particle whose motion is represented by the equation $S = 4t^3 - 8t^2 + 5t + 4$ is $......$ (in $m \ s^{-2}$)

Draw the $x-t$ graphs for positive,negative,and zero acceleration.

At any instant,the velocity and acceleration of a particle moving along a straight line are $v$ and $a$. The speed of the particle is increasing if

If the displacement ($s$ in metre) of a moving particle in terms of time ($t$ in second) is $s = t^3 - 6t^2 + 18t + 9$,then the minimum velocity attained by the particle is (in $m \ s^{-1}$)

If $v = x^2 - 5x + 4$,find the acceleration of the particle when the velocity of the particle is zero.