The velocity-time graph of a body moving in a | vedclass

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Question

(A) Displacement is the algebraic sum of the areas under the velocity-time graph.Displacement $= A_1 + (-A_2) + A_3$$= (2 \, s 	imes 4 \, m/s) + (2 \

Vedclass · Accepted Answer

$8 \, m, 16 \, m$

Vedclass · Answer

(A) Displacement is the algebraic sum of the areas under the velocity-time graph.Displacement $= A_1 + (-A_2) + A_3$$= (2 \, s 	imes 4 \, m/s) + (2 \, s 	imes -2 \, m/s) + (2 \, s 	imes 2 \, m/s)$$= 8 \, m - 4 \, m + 4 \, m = 8 \, m$Distance is the sum of the magnitudes of the areas under the velocity-time graph.Distance $= |A_1| + |A_2| + |A_3|$$= |8 \, m| + |-4 \, m| + |4 \, m|$$= 8 \, m + 4 \, m + 4 \, m = 16 \, m$Thus,the displacement is $8 \, m$ and the distance is $16 \, m$.

The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in $6 \, s$ are respectively:

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