The vertex of the parabola $(y - 2)^2 = 16(x - 1)$ is

What is the equation of the normal to the parabola $y^2 = 4ax$ at the point $(\frac{a}{m^2}, \frac{2a}{m})$?

If $Q$ is the point on the parabola $y^2=4x$ that is nearest to the point $P(2,0)$, then $PQ=$

Let $P(2,4)$ and $Q(18,-12)$ be the points on the parabola $y^2=8x$. The equation of the straight line having slope $\frac{1}{2}$ and passing through the point of intersection of the tangents to the parabola drawn at the points $P$ and $Q$ is

If a normal drawn to the parabola $y^2 = 4ax$ at the point $(a, 2a)$ meets the parabola again at $(at^2, 2at)$,then the value of $t$ is:

Two perpendicular tangents to the parabola $y^2 = 4ax$ always intersect on the line: