The vertices of Delta PQR are P(2, 3), Q(2, 5 | vedclass

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(A) To determine the type of triangle,we calculate the lengths of the sides using the distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$.$1$. Le

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equilateral

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(A) To determine the type of triangle,we calculate the lengths of the sides using the distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$.$1$. Length of $PQ$: $PQ^2 = (2-2)^2 + (5-3)^2 = 0^2 + 2^2 = 4$. So,$PQ = 2$.$2$. Length of $QR$: $QR^2 = (2+\sqrt{3}-2)^2 + (4-5)^2 = (\sqrt{3})^2 + (-1)^2 = 3 + 1 = 4$. So,$QR = 2$.$3$. Length of $PR$: $PR^2 = (2+\sqrt{3}-2)^2 + (4-3)^2 = (\sqrt{3})^2 + 1^2 = 3 + 1 = 4$. So,$PR = 2$.Since $PQ = QR = PR = 2$,all three sides are equal.Therefore,$\Delta PQR$ is an equilateral triangle.

The vertices of $\Delta PQR$ are $P(2, 3), Q(2, 5)$ and $R(2+\sqrt{3}, 4)$. Then $\Delta PQR$ is a $\dots$ triangle.

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