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(A) The displacement current $I_d$ in a capacitor is equal to the conduction current $I_c$ flowing through the connecting wires,which is given by the

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$4$

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(A) The displacement current $I_d$ in a capacitor is equal to the conduction current $I_c$ flowing through the connecting wires,which is given by the formula $I_d = I_c = C \frac{dV}{dt}$.Given:Capacitance $C = 1 \ \mu F = 1 	imes 10^{-6} \ F$.Rate of change of voltage $\frac{dV}{dt} = 4 \ V/s$.Substituting these values into the formula:$I_d = (1 	imes 10^{-6} \ F) 	imes (4 \ V/s) = 4 	imes 10^{-6} \ A = 4 \ \mu A$.Therefore,the displacement current is $4 \ \mu A$.

The voltage between the plates of a parallel plate capacitor of capacity $1 \ \mu F$ is changing at the rate of $4 \ V/s$. The displacement current in the capacitor is: (in $\mu A$)

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