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(D) The volume of a sphere is given by $V = \frac{4}{3} \pi r^3$.Given the ratio of volumes: $\frac{V_1}{V_2} = \frac{64}{27}$.Since $\frac{V_1}{V_2}

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$16:9$

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(D) The volume of a sphere is given by $V = \frac{4}{3} \pi r^3$.Given the ratio of volumes: $\frac{V_1}{V_2} = \frac{64}{27}$.Since $\frac{V_1}{V_2} = \frac{r_1^3}{r_2^3}$,we have $\frac{r_1^3}{r_2^3} = \frac{64}{27}$.Taking the cube root on both sides: $\frac{r_1}{r_2} = \sqrt[3]{\frac{64}{27}} = \frac{4}{3}$.The surface area of a sphere is given by $A = 4 \pi r^2$.Therefore,the ratio of surface areas is $\frac{A_1}{A_2} = \frac{4 \pi r_1^2}{4 \pi r_2^2} = \frac{r_1^2}{r_2^2}$.Substituting the ratio of radii: $\frac{A_1}{A_2} = \left(\frac{4}{3}\right)^2 = \frac{16}{9}$.Thus,the ratio of their surface areas is $16:9$.

The volumes of two spheres are in the ratio of $64:27$. The ratio of their surface areas is

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