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(D) The most energetic $X$-ray corresponds to the minimum wavelength $(\lambda_{\min})$ produced when the entire kinetic energy of the electron is con

Vedclass · Accepted Answer

$0.124$

Vedclass · Answer

(D) The most energetic $X$-ray corresponds to the minimum wavelength $(\lambda_{\min})$ produced when the entire kinetic energy of the electron is converted into a single photon.Using the Duane-Hunt law,the minimum wavelength is given by the formula:$\lambda_{\min} = \frac{hc}{E} = \frac{12400 	ext{ eV} \cdot \mathring{A}}{E 	ext{ (in eV)}}$Given the energy $E = 100 	ext{ keV} = 100,000 	ext{ eV}$.Substituting the values:$\lambda_{\min} = \frac{12400}{100000} \mathring{A} = 0.124 \mathring{A}$Thus,the correct option is $D$.

The wavelength of the most energetic $X$-ray emitted when a metal target is bombarded by $100 \text{ keV}$ electrons is approximately.......$ \mathring{A} $

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